Cevap:
[tex] {2}^{x + 2} = {4}^{ \times - \frac{1}{2} } \\ {2}^{x} \times {2}^{2} = \frac{ {4}^{x} }{ {4}^{ \frac{1}{2} } } \\ {2}^{x} \times 4 = \frac{ {4}^{x} }{ \sqrt{4} } \\ {2}^{x} \times 4 = \frac{ {4}^{x} }{2} \\ 2 \times 4 \times {2}^{ x} = {2}^{2x} \\ 8 = {2}^{x} \\ x = 3 \\ {8}^{x - 1} = {8}^{3 - 1} = {8}^{2} = 64[/tex]
